What is expand (1-ln(x))(1+ln(x)) ?

The solution to expand (1-ln(x))(1+ln(x)) is 1-ln^2(x)

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expand (1-ln(x))(1+ln(x))

expand

(1 - ln (x)) (1 + ln (x))

1 - ln^{2} (x)

Solution steps

(1 - ln (x)) (1 + ln (x))

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = 1, b = ln (x)

= 1^{2} - ln^{2} (x)

Apply rule

1^{a} = 1

1^{2} = 1

= 1 - ln^{2} (x)

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\frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}} + 2}{3}

What is expand (1-ln(x))(1+ln(x)) ?
The solution to expand (1-ln(x))(1+ln(x)) is 1-ln^2(x)