What is expand (2(1-3^{2/3})^{3/2}+2)/3 ?

The solution to expand (2(1-3^{2/3})^{3/2}+2)/3 is (2(1-3^{2/3})^{3/2})/3+2/3

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expand (2(1-3^{2/3})^{3/2}+2)/3

expand

\frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}} + 2}{3}

\frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}}}{3} + \frac{2}{3}

Solution steps

\frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}} + 2}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}} + 2}{3} = \frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}}}{3} + \frac{2}{3}

= \frac{2 ( 1 - 3 ^{\frac{2}{3}} ) ^{\frac{3}{2}}}{3} + \frac{2}{3}

10 (- 2 e^{- 2 x} + 3 e^{- 3 x})

\frac{x ^{2} + 7 x + 11}{( x + 2 ) ( x + 1 ) ( x + 3 )}

e^{(x^{2} + y^{2})^{2}}

(x^{2} - 1) e^{\frac{1}{x - 3}}

- \frac{e ^{x}}{( c + e ^{x} ) ^{2}}

What is expand (2(1-3^{2/3})^{3/2}+2)/3 ?
The solution to expand (2(1-3^{2/3})^{3/2}+2)/3 is (2(1-3^{2/3})^{3/2})/3+2/3