What is expand (1+x^2)/((2x-1)(3-x)) ?

The solution to expand (1+x^2)/((2x-1)(3-x)) is (1+x^2)/(-2x^2+7x-3)

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expand (1+x^2)/((2x-1)(3-x))

expand

\frac{1 + x ^{2}}{( 2 x - 1 ) ( 3 - x )}

\frac{1 + x ^{2}}{- 2 x ^{2} + 7 x - 3}

Solution steps

\frac{1 + x ^{2}}{( 2 x - 1 ) ( 3 - x )}

Expand

(2 x - 1) (3 - x) : - 2 x^{2} + 7 x - 3

= \frac{1 + x ^{2}}{- 2 x ^{2} + 7 x - 3}

\frac{4 x ^{2} - 8 x + 1}{( x + 2 ) ( x ^{2} - 2 x + 3 )}

π (2 ln (3) + \frac{2}{3})

\frac{- 4 x ^{2} - 10 x - 4}{( x ^{2} - 1 ) ^{2}}

(- 2, 2) y (3, - 5)

\frac{( x + 1 ) ^{2}}{1 + x ^{2}}

What is expand (1+x^2)/((2x-1)(3-x)) ?
The solution to expand (1+x^2)/((2x-1)(3-x)) is (1+x^2)/(-2x^2+7x-3)