What is expand ((x+1)-(e^{8x-8}))^2 ?

The solution to expand ((x+1)-(e^{8x-8}))^2 is x^2+2x-2e^{8x-8}x-2e^{8x-8}+e^{16x-16}+1

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expand ((x+1)-(e^{8x-8}))^2

expand

((x + 1) - (e^{8 x - 8}))^{2}

x^{2} + 2 x - 2 e^{8 x - 8} x - 2 e^{8 x - 8} + e^{16 x - 16} + 1

Solution steps

((x + 1) - (e^{8 x - 8}))^{2}

Remove parentheses:

(a) = a

= (x + 1 - e^{8 x - 8})^{2}

(x + 1 - e^{8 x - 8})^{2} = (x + 1 - e^{8 x - 8}) (x + 1 - e^{8 x - 8})

= (x - e^{8 x - 8} + 1) (x - e^{8 x - 8} + 1)

Expand

(x + 1 - e^{8 x - 8}) (x + 1 - e^{8 x - 8}) : x^{2} + 2 x - 2 e^{8 x - 8} x - 2 e^{8 x - 8} + e^{16 x - 16} + 1

= x^{2} + 2 x - 2 e^{8 x - 8} x - 2 e^{8 x - 8} + e^{16 x - 16} + 1

\frac{1}{( x ^{2} + 1 ) ( x + 2 )}

[\frac{2 s ^{3} + 3 s ^{2} + 2 s + 27}{( s ^{2} + 9 ) ( s ^{2} + 1 )}]

x e^{6 x y} (y e^{6 x y} + x)

\frac{1 - x}{( 2 - x ) ^{2}}

\frac{x ^{2} ( 9 - x ^{2} )}{( 3 - x ^{2} ) ^{2}}

What is expand ((x+1)-(e^{8x-8}))^2 ?
The solution to expand ((x+1)-(e^{8x-8}))^2 is x^2+2x-2e^{8x-8}x-2e^{8x-8}+e^{16x-16}+1