What is expand e((-pi+1+pi^2)/(pi^2-pi)-1) ?

The solution to expand e((-pi+1+pi^2)/(pi^2-pi)-1) is e(-pi+1+pi^2)/(pi^2-pi)-1e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e((-pi+1+pi^2)/(pi^2-pi)-1)

expand

e (\frac{- π + 1 + π ^{2}}{π ^{2} - π} - 1)

e \frac{- π + 1 + π ^{2}}{π ^{2} - π} - 1 e

Solution steps

e (\frac{- π + 1 + π ^{2}}{π ^{2} - π} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = e, b = \frac{- π + 1 + π ^{2}}{π ^{2} - π}, c = 1

= e \frac{- π + 1 + π ^{2}}{π ^{2} - π} - e 1

= e \frac{- π + 1 + π ^{2}}{π ^{2} - π} - 1 e

\frac{k ( s + 1 )}{s ^{2} ( s + 10 ) ( s + 100 )}

\frac{1 - e ^{- 2 s}}{s ( s ^{2} + 4 )}

H (x - 2) (t - 2)^{2}

\frac{4 e ^{- s} - 2 s e ^{- s} - s ^{2} + s}{s ( s - 1 )}

(1 - cos (θ))^{2} + sin^{2} (θ)

What is expand e((-pi+1+pi^2)/(pi^2-pi)-1) ?
The solution to expand e((-pi+1+pi^2)/(pi^2-pi)-1) is e(-pi+1+pi^2)/(pi^2-pi)-1e