What is expand ((x+2)(x+1)(2x+3))/((x+2)(x+1)) ?

The solution to expand ((x+2)(x+1)(2x+3))/((x+2)(x+1)) is 2x+3

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expand ((x+2)(x+1)(2x+3))/((x+2)(x+1))

expand

\frac{( x + 2 ) ( x + 1 ) ( 2 x + 3 )}{( x + 2 ) ( x + 1 )}

2 x + 3

Solution steps

\frac{( x + 2 ) ( x + 1 ) ( 2 x + 3 )}{( x + 2 ) ( x + 1 )}

Cancel the common factor:

x + 2

= \frac{( x + 1 ) ( 2 x + 3 )}{x + 1}

Cancel the common factor:

x + 1

= 2 x + 3

\frac{( n + 1 ) ( n + 2 ) ( 2 n + 9 )}{6}

\frac{2}{x ( x ^{2} - 16 )}

f (x) = \frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}}

\frac{100 a ^{2} - 20 a + 1}{100}

(y^{'} (x) + (1 - sec (x)) y^{2}) tan (x)

What is expand ((x+2)(x+1)(2x+3))/((x+2)(x+1)) ?
The solution to expand ((x+2)(x+1)(2x+3))/((x+2)(x+1)) is 2x+3