What is expand 64sin(θ)+64cos(θ)sin(θ) ?

The solution to expand 64sin(θ)+64cos(θ)sin(θ) is 64sin(θ)+32sin(2θ)

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expand 64sin(θ)+64cos(θ)sin(θ)

expand

64 sin (θ) + 64 cos (θ) sin (θ)

64 sin (θ) + 32 sin (2 θ)

Solution steps

64 sin (θ) + 64 cos (θ) sin (θ)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= 64 \cdot \frac{sin ( 2 θ )}{2}

Simplify

64 \cdot \frac{sin ( 2 θ )}{2} : 32 sin (2 θ)

= 64 sin (θ) + 32 sin (2 θ)

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\frac{( 100 \cdot ( s + 25 ) )}{( s \cdot ( s + 5 ) ^{3} )}

\frac{\partial}{\partial x} ((y) (x^{4} + y^{4}))

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What is expand 64sin(θ)+64cos(θ)sin(θ) ?
The solution to expand 64sin(θ)+64cos(θ)sin(θ) is 64sin(θ)+32sin(2θ)