What is expand (2+j+k)(1-2+2)(3-4=2k) ?

The solution to expand (2+j+k)(1-2+2)(3-4=2k) is -2=2k

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expand (2+j+k)(1-2+2)(3-4=2k)

expand

(2 + j + k) (1 - 2 + 2) (3 - 4 = 2 k)

- 2 = 2 k

Solution steps

(2 + j + k) (1 - 2 + 2) (3 - 4 = 2 k)

= (1 - 2 + 2) (2 + j + k) (3 - 4 \cdot 2 = k)

Expand

(2 + j + k) (1 - 2 + 2) : 2 + j + k

= (2 + j + k) (3 - 4 = 2 k)

Expand

(2 + j + k) (3 - 4 = 2 k) : - 2 = 2 k

- 2 = 2 k

\frac{3 x ^{2} - 7 x - 12}{( x + 4 ) ( x - 4 ) ^{2}}

3 sin (2 (π - θ))

\frac{( e ^{- s} )}{s ( s + 1 )}

\frac{1}{( x - 2 ) ( x + 2 )}

(\frac{s ^{2} + s + 1}{s ( s + 1 )}) + 1

What is expand (2+j+k)(1-2+2)(3-4=2k) ?
The solution to expand (2+j+k)(1-2+2)(3-4=2k) is -2=2k