What is expand-2[(y-10)/5 ]^2 ?

The solution to expand-2[(y-10)/5 ]^2 is -(2y^2}{25}+\frac{8y)/5-8

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expand-2[(y-10)/5 ]^2

expand

- 2 [\frac{y - 10}{5}]^{2}

- \frac{2 y ^{2}}{25} + \frac{8 y}{5} - 8

Solution steps

- 2 (\frac{y - 10}{5})^{2}

(\frac{y - 10}{5})^{2} = \frac{y ^{2} - 20 y + 100}{5 ^{2}}

= - 2 \cdot \frac{y ^{2} - 20 y + 100}{5 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{( y ^{2} - 20 y + 100 ) \cdot 2}{5 ^{2}}

5^{2} = 25

= - \frac{2 ( y ^{2} - 20 y + 100 )}{25}

Expand

(y^{2} - 20 y + 100) \cdot 2 : 2 y^{2} - 40 y + 200

= - \frac{2 y ^{2} - 40 y + 200}{25}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 y ^{2} - 40 y + 200}{25} = - (\frac{2 y ^{2}}{25}) - (- \frac{40 y}{25}) - (\frac{200}{25})

= - (\frac{2 y ^{2}}{25}) - (- \frac{40 y}{25}) - (\frac{200}{25})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{2 y ^{2}}{25} + \frac{40 y}{25} - \frac{200}{25}

Cancel

\frac{40 y}{25} : \frac{8 y}{5}

= - \frac{2 y ^{2}}{25} + \frac{8 y}{5} - \frac{200}{25}

Divide the numbers:

\frac{200}{25} = 8

= - \frac{2 y ^{2}}{25} + \frac{8 y}{5} - 8

y^{(4)} t - (λ + 1) y^{'''} (t) + λ y^{''} (t)

5 ((4, 0, - 8) - 8 (6, - 1, - 4))

\frac{5 ( 3 + 3 )}{3}

- 3 (27 π^{3} - 1)

\frac{16}{( s ^{2} + 4 ) ^{2}}

What is expand-2[(y-10)/5 ]^2 ?
The solution to expand-2[(y-10)/5 ]^2 is -(2y^2}{25}+\frac{8y)/5-8