What is expand (2^x+3^x)^2dz ?

The solution to expand (2^x+3^x)^2dz is 4^xdz+3^x*2^{1+x}dz+9^xdz

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expand (2^x+3^x)^2dz

expand

(2^{x} + 3^{x})^{2} d z

4^{x} d z + 3^{x} \cdot 2^{1 + x} d z + 9^{x} d z

Solution steps

(2^{x} + 3^{x})^{2} d z

(2^{x} + 3^{x})^{2} = 4^{x} + 3^{x} \cdot 2^{1 + x} + 9^{x}

= (4^{x} + 3^{x} \cdot 2^{x + 1} + 9^{x}) d z

Distribute parentheses

= d z \cdot 4^{x} + d z \cdot 3^{x} \cdot 2^{1 + x} + d z \cdot 9^{x}

= 4^{x} d z + 3^{x} \cdot 2^{1 + x} d z + 9^{x} d z

\frac{n ( 4 n ^{2} + 6 n + 3 )}{4 ( n + 1 ) ^{2}}

\frac{2 ( x ) ^{3} + ( x ) - 1}{( ( x ) + 1 ) ( ( x ) + 2 ) ( ( x ) - 2 )}

\frac{\partial}{\partial x} ((z) (x^{4} - 4 x y + 9 y^{3}))

\frac{1}{( x + 1 ) \cdot ( x ^{3} - 1 )}

What is expand (2^x+3^x)^2dz ?
The solution to expand (2^x+3^x)^2dz is 4^xdz+3^x*2^{1+x}dz+9^xdz