What is expand (1/((3+h)^2))-(1/9) ?

The solution to expand (1/((3+h)^2))-(1/9) is 1/(9+6h+h^2)-1/9

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expand (1/((3+h)^2))-(1/9)

expand

(\frac{1}{( 3 + h ) ^{2}}) - (\frac{1}{9})

\frac{1}{9 + 6 h + h ^{2}} - \frac{1}{9}

Solution steps

(\frac{1}{( 3 + h ) ^{2}}) - (\frac{1}{9})

Remove parentheses:

(a) = a

= \frac{1}{( 3 + h ) ^{2}} - \frac{1}{9}

(3 + h)^{2} = 9 + 6 h + h^{2}

= \frac{1}{h ^{2} + 6 h + 9} - \frac{1}{9}

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What is expand (1/((3+h)^2))-(1/9) ?
The solution to expand (1/((3+h)^2))-(1/9) is 1/(9+6h+h^2)-1/9