What is expand e^{-4t-8}h(t-2) ?

The solution to expand e^{-4t-8}h(t-2) is e^{-4t-8}th-2e^{-4t-8}h

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expand e^{-4t-8}h(t-2)

expand

e^{- 4 t - 8} h (t - 2)

e^{- 4 t - 8} t h - 2 e^{- 4 t - 8} h

Solution steps

e^{- 4 t - 8} h (t - 2)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{- 4 t - 8} h, b = t, c = 2

= e^{- 4 t - 8} h t - e^{- 4 t - 8} h \cdot 2

= e^{- 4 t - 8} t h - 2 e^{- 4 t - 8} h

sin (3 (180 - θ))

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\frac{d}{d x} ((8 x + 3) (x^{2} - 1)) + \frac{x + 4}{5}

(A x^{2} + B x + C) e^{3 x}

What is expand e^{-4t-8}h(t-2) ?
The solution to expand e^{-4t-8}h(t-2) is e^{-4t-8}th-2e^{-4t-8}h