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Popular >

expand derivative of (8x+3(x^2-1))+(x+4)/5

Solution

expand

\frac{d}{d x} ((8 x + 3) (x^{2} - 1)) + \frac{x + 4}{5}

Solution

\frac{d}{d x} (8 x^{3} - 8 x + 3 x^{2} - 3) + \frac{x}{5} + \frac{4}{5}

Solution steps

\frac{d}{d x} ((8 x + 3) (x^{2} - 1)) + \frac{x + 4}{5}

Expand

(8 x + 3) (x^{2} - 1) : 8 x^{3} - 8 x + 3 x^{2} - 3

= \frac{d}{d x} (8 x^{3} + 3 x^{2} - 8 x - 3) + \frac{x + 4}{5}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x + 4}{5} = \frac{x}{5} + \frac{4}{5}

= \frac{d}{d x} (8 x^{3} + 3 x^{2} - 8 x - 3) + \frac{x}{5} + \frac{4}{5}

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Frequently Asked Questions (FAQ)

What is expand derivative of (8x+3(x^2-1))+(x+4)/5 ?
The solution to expand derivative of (8x+3(x^2-1))+(x+4)/5 is derivative of 8x^3-8x+3x^2-3+x/5+4/5