What is expand (7*2^{k+1}+(-1)^{k+2})/3 ?

The solution to expand (7*2^{k+1}+(-1)^{k+2})/3 is (7*2^{k+1})/3+((-1)^{k+2})/3

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expand (7*2^{k+1}+(-1)^{k+2})/3

expand

\frac{7 \cdot 2 ^{k + 1} + ( - 1 ) ^{k + 2}}{3}

\frac{7 \cdot 2 ^{k + 1}}{3} + \frac{( - 1 ) ^{k + 2}}{3}

Solution steps

\frac{7 \cdot 2 ^{k + 1} + ( - 1 ) ^{k + 2}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{7 \cdot 2 ^{k + 1} + ( - 1 ) ^{k + 2}}{3} = \frac{7 \cdot 2 ^{k + 1}}{3} + \frac{( - 1 ) ^{k + 2}}{3}

= \frac{7 \cdot 2 ^{k + 1}}{3} + \frac{( - 1 ) ^{k + 2}}{3}

\frac{( 2 x - 1 ) ( x + 1 )}{2}

2 sin (3 t) [u (t - 2)]

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e^{x} (1 - e^{- x})

\frac{\partial}{\partial x} ((z) (yz - ln (x + z)))

What is expand (7*2^{k+1}+(-1)^{k+2})/3 ?
The solution to expand (7*2^{k+1}+(-1)^{k+2})/3 is (7*2^{k+1})/3+((-1)^{k+2})/3