What are the solutions to the equation x^2+14x+49=0 ?

The solutions to the equation x^2+14x+49=0 are x=-7

Find the zeros of x^2+14x+49=0

The zeros of x^2+14x+49=0 are x=-7

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x^{2} + 14 x + 49 = 0

x = - 7

Solution steps

x^{2} + 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

x = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

x = - 7

The solution to the quadratic equation is:

x = - 7

\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5}

2 x^{2} + 7 x + 3 = 0

(- i)^{5}

\frac{x}{x + 3} > 0

5 x^{2} - 34 x - 7 = 0

What are the solutions to the equation x^2+14x+49=0 ?
The solutions to the equation x^2+14x+49=0 are x=-7
Find the zeros of x^2+14x+49=0
The zeros of x^2+14x+49=0 are x=-7