What is expand (5(k+1)(k+2))/2 ?

The solution to expand (5(k+1)(k+2))/2 is (5k^2)/2+(15k)/2+5

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expand (5(k+1)(k+2))/2

expand

\frac{5 ( k + 1 ) ( k + 2 )}{2}

\frac{5 k ^{2}}{2} + \frac{15 k}{2} + 5

Solution steps

\frac{5 ( k + 1 ) ( k + 2 )}{2}

Expand

5 (k + 1) (k + 2) : 5 k^{2} + 15 k + 10

= \frac{5 k ^{2} + 15 k + 10}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{5 k ^{2} + 15 k + 10}{2} = \frac{5 k ^{2}}{2} + \frac{15 k}{2} + \frac{10}{2}

= \frac{5 k ^{2}}{2} + \frac{15 k}{2} + \frac{10}{2}

Divide the numbers:

\frac{10}{2} = 5

= \frac{5 k ^{2}}{2} + \frac{15 k}{2} + 5

- \frac{1}{( x + 1 ) ( x - 1 ) ( x ^{2} + 1 )}

\frac{x \cdot ( x - 1 ) \cdot ( x - 2 )}{6}

(2 \cdot (- 3) y = - 1,) (k x + (k - 1) y - 2 (k + 2) = 0,)

\frac{5 x ^{2} - 26 x + 21}{( - x + 5 ) ( - x + 3 )}

(ln (x) - 1)^{2}

What is expand (5(k+1)(k+2))/2 ?
The solution to expand (5(k+1)(k+2))/2 is (5k^2)/2+(15k)/2+5