What is expand 1/((2k+2)!(2k+1)(2k+2)) ?

The solution to expand 1/((2k+2)!(2k+1)(2k+2)) is 1/(4k^2(2k+2)!+6k(2k+2)!+2(2k+2)!)

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expand 1/((2k+2)!(2k+1)(2k+2))

expand

\frac{1}{( 2 k + 2 ) ! ( 2 k + 1 ) ( 2 k + 2 )}

\frac{1}{4 k ^{2} ( 2 k + 2 ) ! + 6 k ( 2 k + 2 ) ! + 2 ( 2 k + 2 ) !}

Solution steps

\frac{1}{( 2 k + 2 ) ! ( 2 k + 1 ) ( 2 k + 2 )}

Expand

(2 k + 2)! (2 k + 1) (2 k + 2) : 4 k^{2} (2 k + 2)! + 6 k (2 k + 2)! + 2 (2 k + 2)!

= \frac{1}{4 k ^{2} ( 2 k + 2 ) ! + 6 k ( 2 k + 2 ) ! + 2 ( 2 k + 2 ) !}

\frac{- 4 x ^{2} + 3 x + 6}{2 ( 2 x + 1 ) ( 3 x - 2 )}

(7, 1) y (7, - 5)

\frac{9 x ^{3} + 3 x ^{2} y - 5 x y ^{2} + y ^{3}}{( 3 x - y ) ( x + y )}

sin (3 3^{\circ} + 4 2^{\circ})

- \frac{( x + 1 ) ^{3} ( 3 ln ( x + 1 ) + 1 )}{9}

What is expand 1/((2k+2)!(2k+1)(2k+2)) ?
The solution to expand 1/((2k+2)!(2k+1)(2k+2)) is 1/(4k^2(2k+2)!+6k(2k+2)!+2(2k+2)!)