What is expand (v^2+13)/((v-9)(v+4)) ?

The solution to expand (v^2+13)/((v-9)(v+4)) is (v^2+13)/(v^2-5v-36)

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expand (v^2+13)/((v-9)(v+4))

expand

\frac{v ^{2} + 13}{( v - 9 ) ( v + 4 )}

\frac{v ^{2} + 13}{v ^{2} - 5 v - 36}

Solution steps

\frac{v ^{2} + 13}{( v - 9 ) ( v + 4 )}

Expand

(v - 9) (v + 4) : v^{2} - 5 v - 36

= \frac{v ^{2} + 13}{v ^{2} - 5 v - 36}

\frac{\partial}{\partial x} ((y) (2 x + y))

\frac{sin ( ( 2 k + 1 ) 2 π )}{2 k + 1}

\frac{- 2 s ^{3} + 6 s ^{2} - 17 s + 54}{( s ^{2} + 9 ) ^{2}}

\frac{2 ( 5 + 2 \cdot 5 ^{\frac{1}{2}} )}{5}

(\frac{1}{3} e^{x} + \frac{5}{3} e^{- 2 x}) \cdot (e^{x} - 2 y)

What is expand (v^2+13)/((v-9)(v+4)) ?
The solution to expand (v^2+13)/((v-9)(v+4)) is (v^2+13)/(v^2-5v-36)