What is expand (sin((2k+1)2pi))/(2k+1) ?

The solution to expand (sin((2k+1)2pi))/(2k+1) is (sin(4pik))/(2k+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (sin((2k+1)2pi))/(2k+1)

expand

\frac{sin ( ( 2 k + 1 ) 2 π )}{2 k + 1}

\frac{sin ( 4 πk )}{2 k + 1}

Solution steps

\frac{sin ( ( 2 k + 1 ) \cdot 2 π )}{2 k + 1}

Expand

(2 k + 1) \cdot 2 π : 4 πk + 2 π

= \frac{sin ( 4 πk + 2 π )}{2 k + 1}

Rewrite using trig identities

= \frac{sin ( 4 πk )}{2 k + 1}

\frac{- 2 s ^{3} + 6 s ^{2} - 17 s + 54}{( s ^{2} + 9 ) ^{2}}

\frac{2 ( 5 + 2 \cdot 5 ^{\frac{1}{2}} )}{5}

(\frac{1}{3} e^{x} + \frac{5}{3} e^{- 2 x}) \cdot (e^{x} - 2 y)

a (- 2, 4) b (1, 2) c (0, - 3)

5^{(n - 1)} + 2^{(n - 1)}

What is expand (sin((2k+1)2pi))/(2k+1) ?
The solution to expand (sin((2k+1)2pi))/(2k+1) is (sin(4pik))/(2k+1)