What is expand a(-2,4)b(1,2)c(0,-3) ?

The solution to expand a(-2,4)b(1,2)c(0,-3) is 0*(-2*4,)(1*2,)abc,-3(-2*4,)(1*2,)abc

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expand a(-2,4)b(1,2)c(0,-3)

expand

a (- 2, 4) b (1, 2) c (0, - 3)

0 \cdot (- 2 \cdot 4,) (1 \cdot 2,) ab c, - 3 (- 2 \cdot 4,) (1 \cdot 2,) ab c

Solution steps

a (- 2, 4) b (1, 2) c (0, - 3)

= (- 2 \cdot 4,) (1 \cdot 2,) (0, - 3) ab c

Apply the distributive law:

a (b - c) = ab - a c

a = a (- 2, 4) b (1, 2) c, b = 0,, c = 3

= a (- 2, 4) b (1, 2) c \cdot 0, - a (- 2, 4) b (1, 2) c \cdot 3

= 0 \cdot (- 2 \cdot 4,) (1 \cdot 2,) ab c, - 3 (- 2 \cdot 4,) (1 \cdot 2,) ab c

5^{(n - 1)} + 2^{(n - 1)}

\frac{\partial}{\partial x} ((z) (z^{x} - 4 x y^{3} + z))

\frac{\partial}{\partial x} ((z) (3 x^{4} - 2 y^{3})^{3})

(\frac{1}{2}, \frac{7}{2}) y (- \frac{8}{5}, - \frac{6}{5})

- \frac{( 4 - 3 π ) a ^{3}}{18}

What is expand a(-2,4)b(1,2)c(0,-3) ?
The solution to expand a(-2,4)b(1,2)c(0,-3) is 0*(-2*4,)(1*2,)abc,-3(-2*4,)(1*2,)abc