What is expand (1/2 , 7/2)y(-8/5 ,-6/5) ?

The solution to expand (1/2 , 7/2)y(-8/5 ,-6/5) is -8/5 (1/2*7/2 ,)y,-6/5 (1/2*7/2 ,)y

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expand (1/2 , 7/2)y(-8/5 ,-6/5)

expand

(\frac{1}{2}, \frac{7}{2}) y (- \frac{8}{5}, - \frac{6}{5})

- \frac{8}{5} (\frac{1}{2} \cdot \frac{7}{2},) y, - \frac{6}{5} (\frac{1}{2} \cdot \frac{7}{2},) y

Solution steps

(\frac{1}{2}, \frac{7}{2}) y (- \frac{8}{5}, - \frac{6}{5})

= (\frac{1}{2} \cdot \frac{7}{2},) (- \frac{8}{5}, - \frac{6}{5}) y

Apply the distributive law:

a (b - c) = ab - a c

a = (\frac{1}{2}, \frac{7}{2}) y, b = - \frac{8}{5},, c = \frac{6}{5}

= (\frac{1}{2}, \frac{7}{2}) y (- \frac{8}{5},) - (\frac{1}{2}, \frac{7}{2}) y \frac{6}{5}

Apply minus-plus rules

+ (- a) = - a

= - \frac{8}{5} (\frac{1}{2} \cdot \frac{7}{2},) y, - \frac{6}{5} (\frac{1}{2} \cdot \frac{7}{2},) y

- \frac{( 4 - 3 π ) a ^{3}}{18}

(e^{10} - 1)^{2}

8 + (8 - cos (4 t)) U (t - 2 π)

\frac{lo g _{10} ( x )}{( 1 + lo g _{10} ( x ) ) ^{2}}

ux (u d x + x d u)

What is expand (1/2 , 7/2)y(-8/5 ,-6/5) ?
The solution to expand (1/2 , 7/2)y(-8/5 ,-6/5) is -8/5 (1/2*7/2 ,)y,-6/5 (1/2*7/2 ,)y