What is expand ((16x^2-1)^2)/(64x^2) ?

The solution to expand ((16x^2-1)^2)/(64x^2) is 4x^2-1/2+1/(64x^2)

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expand ((16x^2-1)^2)/(64x^2)

expand

\frac{( 16 x ^{2} - 1 ) ^{2}}{64 x ^{2}}

4 x^{2} - \frac{1}{2} + \frac{1}{64 x ^{2}}

Solution steps

\frac{( 16 x ^{2} - 1 ) ^{2}}{64 x ^{2}}

(16 x^{2} - 1)^{2} = 256 x^{4} - 32 x^{2} + 1

= \frac{256 x ^{4} - 32 x ^{2} + 1}{64 x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 x ^{4} - 32 x ^{2} + 1}{64 x ^{2}} = \frac{256 x ^{4}}{64 x ^{2}} - \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

= \frac{256 x ^{4}}{64 x ^{2}} - \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

Cancel

\frac{256 x ^{4}}{64 x ^{2}} : 4 x^{2}

= 4 x^{2} - \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

Cancel

\frac{32 x ^{2}}{64 x ^{2}} : \frac{1}{2}

= 4 x^{2} - \frac{1}{2} + \frac{1}{64 x ^{2}}

- \frac{10 x ^{2} + 6}{( x ^{2} + x + 1 ) ( x ^{2} - x + 1 )}

- \frac{3}{( s + 2 ) ( s + 1 )}

(x^{2} + 2)^{12}

(x - 1)^{2} (e^{x} - 1)

\frac{- 4 s - 11}{( s + 2 ) ^{2}}

What is expand ((16x^2-1)^2)/(64x^2) ?
The solution to expand ((16x^2-1)^2)/(64x^2) is 4x^2-1/2+1/(64x^2)