What is expand ((x+2)(2x-1))/2 ?

The solution to expand ((x+2)(2x-1))/2 is x^2+(3x)/2-1

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expand ((x+2)(2x-1))/2

expand

\frac{( x + 2 ) ( 2 x - 1 )}{2}

x^{2} + \frac{3 x}{2} - 1

Solution steps

\frac{( x + 2 ) ( 2 x - 1 )}{2}

Expand

(x + 2) (2 x - 1) : 2 x^{2} + 3 x - 2

= \frac{2 x ^{2} + 3 x - 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 3 x - 2}{2} = \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{2}{2}

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - 1

Divide the numbers:

\frac{2}{2} = 1

= x^{2} + \frac{3 x}{2} - 1

(r + e)^{3} + (r + e)^{2}

\frac{p ( x )}{( x - 1 ) ( x + 1 ) ( x - 2 ) ( x + 2 )}

\frac{4}{s ^{2} ( s + 2 )}

\frac{1}{p ( 1 - p )}

2 (2 e^{- x} x - e^{- x} x^{2})

What is expand ((x+2)(2x-1))/2 ?
The solution to expand ((x+2)(2x-1))/2 is x^2+(3x)/2-1