What is expand (3x^2-5x-52)/((x+2)(x-4)(x+5)) ?

The solution to expand (3x^2-5x-52)/((x+2)(x-4)(x+5)) is (3x^2-5x-52)/(x^3+3x^2-18x-40)

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expand (3x^2-5x-52)/((x+2)(x-4)(x+5))

expand

\frac{3 x ^{2} - 5 x - 52}{( x + 2 ) ( x - 4 ) ( x + 5 )}

\frac{3 x ^{2} - 5 x - 52}{x ^{3} + 3 x ^{2} - 18 x - 40}

Solution steps

\frac{3 x ^{2} - 5 x - 52}{( x + 2 ) ( x - 4 ) ( x + 5 )}

Expand

(x + 2) (x - 4) (x + 5) : x^{3} + 3 x^{2} - 18 x - 40

= \frac{3 x ^{2} - 5 x - 52}{x ^{3} + 3 x ^{2} - 18 x - 40}

3 sin (2 (π + θ))

(8 y + 10 x) d x + (5 y + 7 x) d y

f (x + π)

sin (x) + e^{x} (4 x^{2} + 5 x)

\frac{2 ^{x}}{( 2 ^{x + 1} - 1 ) ( 2 ^{x} - 1 )}

What is expand (3x^2-5x-52)/((x+2)(x-4)(x+5)) ?
The solution to expand (3x^2-5x-52)/((x+2)(x-4)(x+5)) is (3x^2-5x-52)/(x^3+3x^2-18x-40)