What is expand (2^x)/((2^{x+1)-1)(2^x-1)} ?

The solution to expand (2^x)/((2^{x+1)-1)(2^x-1)} is (2^x)/(2^{2x+1)-3*2^x+1}

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expand (2^x)/((2^{x+1)-1)(2^x-1)}

expand

\frac{2 ^{x}}{( 2 ^{x + 1} - 1 ) ( 2 ^{x} - 1 )}

\frac{2 ^{x}}{2 ^{2 x + 1} - 3 \cdot 2 ^{x} + 1}

Solution steps

\frac{2 ^{x}}{( 2 ^{x + 1} - 1 ) ( 2 ^{x} - 1 )}

Expand

(2^{x + 1} - 1) (2^{x} - 1) : 2^{2 x + 1} - 3 \cdot 2^{x} + 1

= \frac{2 ^{x}}{2 ^{2 x + 1} - 3 \cdot 2 ^{x} + 1}

\frac{- 0.1 s + 1}{( s + 0.1 ) ( 0.01 s + 1 )}

\frac{1}{x ^{3} ( x + 1 )}

\frac{4 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

(1 + ab f) {1 + (c + d) e h} e - (ab e (c + d) g)

A (3, 4) B (8, - 6)

What is expand (2^x)/((2^{x+1)-1)(2^x-1)} ?
The solution to expand (2^x)/((2^{x+1)-1)(2^x-1)} is (2^x)/(2^{2x+1)-3*2^x+1}