What is expand (4(3x^2-1))/((x^2+1)^3) ?

The solution to expand (4(3x^2-1))/((x^2+1)^3) is (12x^2-4)/(x^6+3x^4+3x^2+1)

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expand (4(3x^2-1))/((x^2+1)^3)

expand

\frac{4 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

\frac{12 x ^{2} - 4}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

Solution steps

\frac{4 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

(x^{2} + 1)^{3} = x^{6} + 3 x^{4} + 3 x^{2} + 1

= \frac{4 ( 3 x ^{2} - 1 )}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

Expand

4 (3 x^{2} - 1) : 12 x^{2} - 4

= \frac{12 x ^{2} - 4}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

(1 + ab f) {1 + (c + d) e h} e - (ab e (c + d) g)

A (3, 4) B (8, - 6)

\frac{x}{( x ^{2} + 1 ) ( x ^{2} + 2 x + 3 )}

\frac{x ^{7} + 2}{( x ^{2} + x + 1 ) ^{2}}

\frac{2 ^{n}}{( 2 ^{n + 1} - 1 ) ( 2 ^{n} - 1 )}

What is expand (4(3x^2-1))/((x^2+1)^3) ?
The solution to expand (4(3x^2-1))/((x^2+1)^3) is (12x^2-4)/(x^6+3x^4+3x^2+1)