What is expand (2^n)/((2^{n+1)-1)(2^n-1)} ?

The solution to expand (2^n)/((2^{n+1)-1)(2^n-1)} is (2^n)/(2^{2n+1)-2^{n+1}-2^n+1}

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expand (2^n)/((2^{n+1)-1)(2^n-1)}

expand

\frac{2 ^{n}}{( 2 ^{n + 1} - 1 ) ( 2 ^{n} - 1 )}

\frac{2 ^{n}}{2 ^{2 n + 1} - 2 ^{n + 1} - 2 ^{n} + 1}

Solution steps

\frac{2 ^{n}}{( 2 ^{n + 1} - 1 ) ( 2 ^{n} - 1 )}

Expand

(2^{n + 1} - 1) (2^{n} - 1) : 2^{2 n + 1} - 2^{n + 1} - 2^{n} + 1

= \frac{2 ^{n}}{2 ^{2 n + 1} - 2 ^{n + 1} - 2 ^{n} + 1}

\frac{1}{2} (e^{t} - e^{- t})

\frac{d}{d x} ((z) (x^{2} + z^{2}))

(3 x + 4 y = - 2) 5

(x^{2} - 1) y + y^{2} (x + 1) y^{'} (x)

3 (8 π - \frac{64 π - 48 3}{9})

What is expand (2^n)/((2^{n+1)-1)(2^n-1)} ?
The solution to expand (2^n)/((2^{n+1)-1)(2^n-1)} is (2^n)/(2^{2n+1)-2^{n+1}-2^n+1}