What is expand (x^2(-2+x))/6 ?

The solution to expand (x^2(-2+x))/6 is (x^3)/6-(x^2)/3

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expand (x^2(-2+x))/6

expand

\frac{x ^{2} ( - 2 + x )}{6}

\frac{x ^{3}}{6} - \frac{x ^{2}}{3}

Solution steps

\frac{x ^{2} ( - 2 + x )}{6}

Expand

x^{2} (- 2 + x) : - 2 x^{2} + x^{3}

= \frac{- 2 x ^{2} + x ^{3}}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 x ^{2} + x ^{3}}{6} = - \frac{2 x ^{2}}{6} + \frac{x ^{3}}{6}

= - \frac{2 x ^{2}}{6} + \frac{x ^{3}}{6}

Cancel

\frac{2 x ^{2}}{6} : \frac{x ^{2}}{3}

= - \frac{x ^{2}}{3} + \frac{x ^{3}}{6}

Rewrite in standard form

= \frac{x ^{3}}{6} - \frac{x ^{2}}{3}

\frac{1}{3} (13.9 ln (13.9) - 13.9)

(x^{2} + y^{2}) \frac{d y}{d x}

\frac{2 y ( 2 x ^{3} - 3 y x ^{2} )}{( x - y ) ^{2}}

\frac{4 ab}{( a - b ) ( a + b )}

\frac{13}{( 2 x + 1 ) ^{2}}

What is expand (x^2(-2+x))/6 ?
The solution to expand (x^2(-2+x))/6 is (x^3)/6-(x^2)/3