What is (x^{-1}+y^{-1})/(z^{-1)} ?

The solution to (x^{-1}+y^{-1})/(z^{-1)} is ((y+x)z)/(xy)

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simplify (x^{-1}+y^{-1})/(z^{-1)}

simplify

\frac{x ^{- 1} + y ^{- 1}}{z ^{- 1}}

\frac{( y + x ) z}{x y}

Solution steps

\frac{x ^{- 1} + y ^{- 1}}{z ^{- 1}}

Simplify

x^{- 1} + y^{- 1} : \frac{y + x}{x y}

= \frac{\frac{y + x}{x y}}{z ^{- 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{y + x}{x y z ^{- 1}}

Simplify

x y z^{- 1} : \frac{x y}{z}

= \frac{y + x}{\frac{x y}{z}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( y + x ) z}{x y}

y^{4} - 5 y^{2} + 4

n^{2} + n^{2}

lo g_{12} (3) + lo g_{12} (4)

w^{3} + w^{2} - 7 w - 7

16 x^{3} + 54

What is (x^{-1}+y^{-1})/(z^{-1)} ?
The solution to (x^{-1}+y^{-1})/(z^{-1)} is ((y+x)z)/(xy)