What is log_{12}(3)+log_{12}(4) ?

The solution to log_{12}(3)+log_{12}(4) is 1

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simplify log_{12}(3)+log_{12}(4)

simplify

lo g_{12} (3) + lo g_{12} (4)

1

Solution steps

lo g_{12} (3) + lo g_{12} (4)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{12} (3) + lo g_{12} (4) = lo g_{12} (3 \cdot 4)

= lo g_{12} (3 \cdot 4)

Multiply the numbers:

3 \cdot 4 = 12

= lo g_{12} (12)

Apply log rule:

lo g_{a} (a) = 1

= 1

w^{3} + w^{2} - 7 w - 7

16 x^{3} + 54

x^{2} + 20 = - 12 x

(- \frac{x}{2 - x ^{2}})^{2}

m^{- 2}