What are the solutions to the equation x^2+20=-12x ?

The solutions to the equation x^2+20=-12x are x=-2,x=-10

Find the zeros of x^2+20=-12x

The zeros of x^2+20=-12x are x=-2,x=-10

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x^{2} + 20 = - 12 x

x = - 2, x = - 10

Solution steps

x^{2} + 20 = - 12 x

Move

12 x

to the left side

x^{2} + 20 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 20 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 1}, x_{2} = \frac{- 12 - 8}{2 \cdot 1}

x = \frac{- 12 + 8}{2 \cdot 1} : - 2

x = \frac{- 12 - 8}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 2, x = - 10

(- \frac{x}{2 - x ^{2}})^{2}

m^{- 2}

3 - 3 (4 - x)^{2} = 18

49 x^{2} + 25 = 70 x

3 (x - y)^{2} + 2 y (x - y) - 5 y^{2}

What are the solutions to the equation x^2+20=-12x ?
The solutions to the equation x^2+20=-12x are x=-2,x=-10
Find the zeros of x^2+20=-12x
The zeros of x^2+20=-12x are x=-2,x=-10