What is expand ((10x-1)^2)/(100) ?

The solution to expand ((10x-1)^2)/(100) is x^2-x/5+1/100

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expand ((10x-1)^2)/(100)

expand

\frac{( 10 x - 1 ) ^{2}}{100}

x^{2} - \frac{x}{5} + \frac{1}{100}

Solution steps

\frac{( 10 x - 1 ) ^{2}}{100}

(10 x - 1)^{2} = 100 x^{2} - 20 x + 1

= \frac{100 x ^{2} - 20 x + 1}{100}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{100 x ^{2} - 20 x + 1}{100} = \frac{100 x ^{2}}{100} - \frac{20 x}{100} + \frac{1}{100}

= \frac{100 x ^{2}}{100} - \frac{20 x}{100} + \frac{1}{100}

Divide the numbers:

\frac{100}{100} = 1

= x^{2} - \frac{20 x}{100} + \frac{1}{100}

Cancel

\frac{20 x}{100} : \frac{x}{5}

= x^{2} - \frac{x}{5} + \frac{1}{100}

(y x^{2} + y^{2}) d x - x (x + x^{2} + y^{2}) d y

(1, 2, 3) x (- 2, - 2, 4)

\frac{x ^{2} + 20 x + 31}{( x + 2 ) ^{2} ( x - 3 )}

\frac{( 4 x + 1 ) ( 5 x - 1 )}{x ^{2} - 9}

\frac{6 x ^{2} + 20 x + 3}{( 3 x + 5 ) ^{2}}

What is expand ((10x-1)^2)/(100) ?
The solution to expand ((10x-1)^2)/(100) is x^2-x/5+1/100