What are the solutions to the equation 49x^2+25=70x ?

The solutions to the equation 49x^2+25=70x are x= 5/7

Find the zeros of 49x^2+25=70x

The zeros of 49x^2+25=70x are x= 5/7

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49 x^{2} + 25 = 70 x

x = \frac{5}{7}

Decimal Notation

x = 0.71428 \dots

Solution steps

49 x^{2} + 25 = 70 x

Move

70 x

to the left side

49 x^{2} + 25 - 70 x = 0

Write in the standard form

a x^{2} + b x + c = 0

49 x^{2} - 70 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 49 \cdot 25}{2 \cdot 49}

(- 70)^{2} - 4 \cdot 49 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 70 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 70 )}{2 \cdot 49}

\frac{- ( - 70 )}{2 \cdot 49} = \frac{5}{7}

x = \frac{5}{7}

The solution to the quadratic equation is:

x = \frac{5}{7}

3 (x - y)^{2} + 2 y (x - y) - 5 y^{2}

\frac{2}{3} (\frac{x}{8} - \frac{3}{4}) = \frac{x}{2} - \frac{1}{12}

(x - 7) (4 - x) (x + 1) \geq 0

\frac{0.9273}{\frac{π}{45}}

\frac{2 a}{3} - \frac{3 a}{2} = - \frac{5}{2}

What are the solutions to the equation 49x^2+25=70x ?
The solutions to the equation 49x^2+25=70x are x= 5/7
Find the zeros of 49x^2+25=70x
The zeros of 49x^2+25=70x are x= 5/7