What is expand (x+1)(-e^{-x}) ?

The solution to expand (x+1)(-e^{-x}) is -e^{-x}x-e^{-x}

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expand (x+1)(-e^{-x})

expand

(x + 1) (- e^{- x})

- e^{- x} x - e^{- x}

Solution steps

(x + 1) (- e^{- x})

Apply the distributive law:

a (b + c) = ab + a c

a = (- e^{- x}), b = x, c = 1

= (- e^{- x}) x + (- e^{- x}) \cdot 1

= x (- e^{- x}) + 1 \cdot (- e^{- x})

Simplify

x (- e^{- x}) + 1 \cdot (- e^{- x}) : - e^{- x} x - e^{- x}

= - e^{- x} x - e^{- x}

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2 t y - sin (t) + (t^{2} + e^{y}) \frac{d y}{d t}

\frac{n ( 5 n + 7 )}{( n + 1 ) ^{2}}

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What is expand (x+1)(-e^{-x}) ?
The solution to expand (x+1)(-e^{-x}) is -e^{-x}x-e^{-x}