What is expand 1/((x+1)(x^2+2x+2)) ?

The solution to expand 1/((x+1)(x^2+2x+2)) is 1/(x^3+3x^2+4x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((x+1)(x^2+2x+2))

expand

\frac{1}{( x + 1 ) ( x ^{2} + 2 x + 2 )}

\frac{1}{x ^{3} + 3 x ^{2} + 4 x + 2}

Solution steps

\frac{1}{( x + 1 ) ( x ^{2} + 2 x + 2 )}

Expand

(x + 1) (x^{2} + 2 x + 2) : x^{3} + 3 x^{2} + 4 x + 2

= \frac{1}{x ^{3} + 3 x ^{2} + 4 x + 2}

\frac{6 x ^{2} - x - 136}{( x - 5 ) ( x + 4 )}

(2, 0, - 2) y (3, - 3, 0)

\frac{ab ( a ^{4} + b ^{4} )}{a ^{6} + b ^{6}}

(1 - \frac{x}{2})^{\frac{1}{2}}

\frac{1}{( k + 3 ) ( k + 4 )}

What is expand 1/((x+1)(x^2+2x+2)) ?
The solution to expand 1/((x+1)(x^2+2x+2)) is 1/(x^3+3x^2+4x+2)