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Popular >

expand 1/((k+3)(k+4))

Solution

expand

\frac{1}{( k + 3 ) ( k + 4 )}

Solution

\frac{1}{k ^{2} + 7 k + 12}

Solution steps

\frac{1}{( k + 3 ) ( k + 4 )}

Expand

(k + 3) (k + 4) : k^{2} + 7 k + 12

= \frac{1}{k ^{2} + 7 k + 12}

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Frequently Asked Questions (FAQ)

What is expand 1/((k+3)(k+4)) ?
The solution to expand 1/((k+3)(k+4)) is 1/(k^2+7k+12)