What is expand (e^2sin^2(t)-3cos^2(t))(-sin(t)) ?

The solution to expand (e^2sin^2(t)-3cos^2(t))(-sin(t)) is -e^2sin^3(t)+3cos^2(t)sin(t)

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expand (e^2sin^2(t)-3cos^2(t))(-sin(t))

expand

(e^{2} sin^{2} (t) - 3 cos^{2} (t)) (- sin (t))

- e^{2} sin^{3} (t) + 3 cos^{2} (t) sin (t)

Solution steps

(e^{2} sin^{2} (t) - 3 cos^{2} (t)) (- sin (t))

= (- sin (t)) (e^{2} sin^{2} (t) - 3 cos^{2} (t))

Apply the distributive law:

a (b - c) = ab - a c

a = (- sin (t)), b = e^{2} sin^{2} (t), c = 3 cos^{2} (t)

= (- sin (t)) e^{2} sin^{2} (t) - (- sin (t)) \cdot 3 cos^{2} (t)

= e^{2} (- sin (t)) sin^{2} (t) - 3 (- sin (t)) cos^{2} (t)

Simplify

e^{2} (- sin (t)) sin^{2} (t) - 3 (- sin (t)) cos^{2} (t) : - e^{2} sin^{3} (t) + 3 cos^{2} (t) sin (t)

= - e^{2} sin^{3} (t) + 3 cos^{2} (t) sin (t)

\frac{s ^{2} + 5 - e ^{- s}}{s ( s ^{2} + 9 )}

- \frac{2 ( - x ^{2} + x + 3 )}{e ^{x}}

\frac{1}{( ( x - 3 ) ( x - 2 ) )}

(sin (x) - 1) ln (tan (x))

a (25, 12) b (6, - 13)

What is expand (e^2sin^2(t)-3cos^2(t))(-sin(t)) ?
The solution to expand (e^2sin^2(t)-3cos^2(t))(-sin(t)) is -e^2sin^3(t)+3cos^2(t)sin(t)