What is expand (sin(x)-1)ln(tan(x)) ?

The solution to expand (sin(x)-1)ln(tan(x)) is ln(tan(x))sin(x)-ln(tan(x))

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expand (sin(x)-1)ln(tan(x))

expand

(sin (x) - 1) ln (tan (x))

ln (tan (x)) sin (x) - ln (tan (x))

Solution steps

(sin (x) - 1) ln (tan (x))

= ln (tan (x)) (sin (x) - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = ln (tan (x)), b = sin (x), c = 1

= ln (tan (x)) sin (x) - ln (tan (x)) \cdot 1

= ln (tan (x)) sin (x) - 1 \cdot ln (tan (x))

Multiply:

1 \cdot ln (tan (x)) = ln (tan (x))

= ln (tan (x)) sin (x) - ln (tan (x))

a (25, 12) b (6, - 13)

\frac{1}{( 1 - b z ) ( 1 - a z )}

e^{x} (- x e^{- x} - e^{- x})

\frac{200 x ^{2} - 1600 x + 2400}{( x ^{2} - 8 x + 20 ) ^{2}}

\frac{2}{( 2 s + 1 ) ( s + 1 )}

What is expand (sin(x)-1)ln(tan(x)) ?
The solution to expand (sin(x)-1)ln(tan(x)) is ln(tan(x))sin(x)-ln(tan(x))