What is expand 3sin(θ^2)-(1+sin(θ))^2dθ ?

The solution to expand 3sin(θ^2)-(1+sin(θ))^2dθ is 3sin(θ^2)-dθ-2sin(θ)dθ-sin^2(θ)dθ

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3sin(θ^2)-(1+sin(θ))^2dθ

expand

3 sin (θ^{2}) - (1 + sin (θ))^{2} d θ

3 sin (θ^{2}) - d θ - 2 sin (θ) d θ - sin^{2} (θ) d θ

Solution steps

3 sin (θ^{2}) - (1 + sin (θ))^{2} d θ

(1 + sin (θ))^{2} = 1 + 2 sin (θ) + sin^{2} (θ)

= 3 sin (θ^{2}) - (sin^{2} (θ) + 2 sin (θ) + 1) d θ

Expand

- d θ (1 + 2 sin (θ) + sin^{2} (θ)) : - d θ - 2 sin (θ) d θ - sin^{2} (θ) d θ

= 3 sin (θ^{2}) - d θ - 2 sin (θ) d θ - sin^{2} (θ) d θ

\frac{2 s - 4}{s ( s + 1 ) ( s ^{2} + 1 )}

\frac{( 10 x ^{2} + y ^{2} + 5 x y ) x y}{5}

\frac{2 + s}{( 100 + s ) ^{2}}

- \frac{1}{( s - 1 ) ^{2} ( s + 2 )}

\frac{( 2 x + 1 ) ( x - 5 )}{3 x + 2}

What is expand 3sin(θ^2)-(1+sin(θ))^2dθ ?
The solution to expand 3sin(θ^2)-(1+sin(θ))^2dθ is 3sin(θ^2)-dθ-2sin(θ)dθ-sin^2(θ)dθ