What is expand ((2x+1)(x-5))/(3x+2) ?

The solution to expand ((2x+1)(x-5))/(3x+2) is (2x^2-9x-5)/(3x+2)

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expand ((2x+1)(x-5))/(3x+2)

expand

\frac{( 2 x + 1 ) ( x - 5 )}{3 x + 2}

\frac{2 x ^{2} - 9 x - 5}{3 x + 2}

Solution steps

\frac{( 2 x + 1 ) ( x - 5 )}{3 x + 2}

Expand

(2 x + 1) (x - 5) : 2 x^{2} - 9 x - 5

= \frac{2 x ^{2} - 9 x - 5}{3 x + 2}

\frac{2 x - 1}{( x + 2 ) ( 3 x ^{2} - 2 x )}

\frac{2 x ^{4} - x ^{3} + 3 x ^{2} - A x + B}{( x + 1 ) ^{2}}

\frac{d}{d t} ((x) (- a x + b))

\frac{e ^{(5 - s) 9}}{5 - s}

c - d {β [π + α (E - N) - X] + r}

What is expand ((2x+1)(x-5))/(3x+2) ?
The solution to expand ((2x+1)(x-5))/(3x+2) is (2x^2-9x-5)/(3x+2)