What is expand y(y-(-7)=-8(x-6)) ?

The solution to expand y(y-(-7)=-8(x-6)) is y^2+7y=-8yx+48y

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expand y(y-(-7)=-8(x-6))

expand

y (y - (- 7) = - 8 (x - 6))

y^{2} + 7 y = - 8 y x + 48 y

Solution steps

y (y - (- 7) = - 8 (x - 6))

Distribute parentheses

= yy + y (- (- 7) =) + y (- 8 (x - 6))

Apply minus-plus rules

+ (- a) = - a

yy - (- 7) y = - 8 y (x - 6)

Simplify

yy - (- 7) y = - 8 y (x - 6) : y^{2} + 7 y = - 8 y x + 48 y

y^{2} + 7 y = - 8 y x + 48 y

d x ((2 x^{3} - 5) (2 x - 4))

e^{y^{2}} \cdot (- y + 1)^{2}

\frac{( 1 - x ^{2} ) sin ( x ) - x cos ( 2 x )}{tan ( x ^{3} )}

y (10, 5, - 2)

\frac{1}{( x - 1 ) ^{2} ( x - 3 )}

What is expand y(y-(-7)=-8(x-6)) ?
The solution to expand y(y-(-7)=-8(x-6)) is y^2+7y=-8yx+48y