What is expand 3/(x+1)+7/(x-4)-5/(x+5) ?

The solution to expand 3/(x+1)+7/(x-4)-5/(x+5) is (5x^2+60x-5)/(x^3+2x^2-19x-20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3/(x+1)+7/(x-4)-5/(x+5)

expand

\frac{3}{x + 1} + \frac{7}{x - 4} - \frac{5}{x + 5}

\frac{5 x ^{2} + 60 x - 5}{x ^{3} + 2 x ^{2} - 19 x - 20}

Solution steps

\frac{3}{x + 1} + \frac{7}{x - 4} - \frac{5}{x + 5}

Least Common Multiplier of

x + 1, x - 4, x + 5 : (x + 1) (x - 4) (x + 5)

Adjust Fractions based on the LCM

= \frac{3 ( x - 4 ) ( x + 5 )}{( x + 1 ) ( x - 4 ) ( x + 5 )} + \frac{7 ( x + 1 ) ( x + 5 )}{( x - 4 ) ( x + 1 ) ( x + 5 )} - \frac{5 ( x + 1 ) ( x - 4 )}{( x + 5 ) ( x + 1 ) ( x - 4 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 ( x - 4 ) ( x + 5 ) + 7 ( x + 1 ) ( x + 5 ) - 5 ( x + 1 ) ( x - 4 )}{( x + 1 ) ( x - 4 ) ( x + 5 )}

Expand

(x + 1) (x - 4) (x + 5) : x^{3} + 2 x^{2} - 19 x - 20

= \frac{3 ( x - 4 ) ( x + 5 ) + 7 ( x + 1 ) ( x + 5 ) - 5 ( x + 1 ) ( x - 4 )}{x ^{3} + 2 x ^{2} - 19 x - 20}

Expand

3 (x - 4) (x + 5) + 7 (x + 1) (x + 5) - 5 (x + 1) (x - 4) : 5 x^{2} + 60 x - 5

= \frac{5 x ^{2} + 60 x - 5}{x ^{3} + 2 x ^{2} - 19 x - 20}

\frac{2 y}{1 + ( x + y ^{2} ) ^{2}}

(e^{2 x} - e^{- 3 x})^{3}

(9 \cdot e^{- 9 \cdot x} + 2)^{3}

π r^{2} (84 - 2 π r)

(1 + 3 e^{- x})^{2}

What is expand 3/(x+1)+7/(x-4)-5/(x+5) ?
The solution to expand 3/(x+1)+7/(x-4)-5/(x+5) is (5x^2+60x-5)/(x^3+2x^2-19x-20)