What is expand sin(2t)U(t-pi) ?

The solution to expand sin(2t)U(t-pi) is tUsin(2t)-piUsin(2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand sin(2t)U(t-pi)

expand

sin (2 t) U (t - π)

t U sin (2 t) - π U sin (2 t)

Solution steps

sin (2 t) U (t - π)

= U sin (2 t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (2 t) U, b = t, c = π

= sin (2 t) U t - sin (2 t) U π

= t U sin (2 t) - π U sin (2 t)

\frac{\partial}{\partial x} ((y) (z + x^{2} + y^{2}))

A (- 4, - \frac{3}{2}) y B (5, - 2)

\frac{( x ^{2} + 6 x + 6 )}{2 ( x ^{2} + 2 x + 2 )}

\frac{2 x ^{4} + a x ^{3} + ( 1 - a ) x ^{2} + a x + ( 3 - a )}{x - 1}

(\frac{10 + x}{x - 2}) (\frac{3}{10 - x})

What is expand sin(2t)U(t-pi) ?
The solution to expand sin(2t)U(t-pi) is tUsin(2t)-piUsin(2t)