What is expand (2(x^2+2x-2))/((x+3)(x+2)^2) ?

The solution to expand (2(x^2+2x-2))/((x+3)(x+2)^2) is (2x^2+4x-4)/(x^3+7x^2+16x+12)

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expand (2(x^2+2x-2))/((x+3)(x+2)^2)

expand

\frac{2 ( x ^{2} + 2 x - 2 )}{( x + 3 ) ( x + 2 ) ^{2}}

\frac{2 x ^{2} + 4 x - 4}{x ^{3} + 7 x ^{2} + 16 x + 12}

Solution steps

\frac{2 ( x ^{2} + 2 x - 2 )}{( x + 3 ) ( x + 2 ) ^{2}}

(x + 2)^{2} = x^{2} + 4 x + 4

= \frac{2 ( x ^{2} + 2 x - 2 )}{( x + 3 ) ( x ^{2} + 4 x + 4 )}

Expand

(x + 3) (x^{2} + 4 x + 4) : x^{3} + 7 x^{2} + 16 x + 12

= \frac{2 ( x ^{2} + 2 x - 2 )}{x ^{3} + 7 x ^{2} + 16 x + 12}

Expand

2 (x^{2} + 2 x - 2) : 2 x^{2} + 4 x - 4

= \frac{2 x ^{2} + 4 x - 4}{x ^{3} + 7 x ^{2} + 16 x + 12}

(3 r + 10)^{+} (3 r + 3)^{=} (5 r - 2)

\frac{0.5 z}{( z - 0.5 ) ( z - 0.7 ) ^{2}}

\frac{s - 2}{( s - 3 ) ( s ^{2} - 1 ) ( s ^{2} + 4 )}

\frac{3 s}{( s + 1 ) ^{4}}

\frac{e ^{- 4 x} ( e ^{8 x} - 1 )}{2}

What is expand (2(x^2+2x-2))/((x+3)(x+2)^2) ?
The solution to expand (2(x^2+2x-2))/((x+3)(x+2)^2) is (2x^2+4x-4)/(x^3+7x^2+16x+12)