What is expand (2s+1)/((s+3)(s^2+4s+13)) ?

The solution to expand (2s+1)/((s+3)(s^2+4s+13)) is (2s+1)/(s^3+7s^2+25s+39)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2s+1)/((s+3)(s^2+4s+13))

expand

\frac{2 s + 1}{( s + 3 ) ( s ^{2} + 4 s + 13 )}

\frac{2 s + 1}{s ^{3} + 7 s ^{2} + 25 s + 39}

Solution steps

\frac{2 s + 1}{( s + 3 ) ( s ^{2} + 4 s + 13 )}

Expand

(s + 3) (s^{2} + 4 s + 13) : s^{3} + 7 s^{2} + 25 s + 39

= \frac{2 s + 1}{s ^{3} + 7 s ^{2} + 25 s + 39}

- \frac{3}{2 ( s ^{2} + s + 1 )}

(e^{x} - e^{- x}) (e^{y} + e^{- y})

\frac{1}{( x + 5 ) ^{2} ( x - 1 )}

f (x) = \frac{8 x + 16}{( x - 1 ) ^{4}}

\frac{16 b ^{2} - 128 b - 1304}{( b - 4 ) ^{2}}

What is expand (2s+1)/((s+3)(s^2+4s+13)) ?
The solution to expand (2s+1)/((s+3)(s^2+4s+13)) is (2s+1)/(s^3+7s^2+25s+39)