What is expand (8(2ln(2)-1))/(e^4) ?

The solution to expand (8(2ln(2)-1))/(e^4) is (16ln(2))/(e^4)-8/(e^4)

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expand (8(2ln(2)-1))/(e^4)

expand

\frac{8 ( 2 ln ( 2 ) - 1 )}{e ^{4}}

\frac{16 ln ( 2 )}{e ^{4}} - \frac{8}{e ^{4}}

Solution steps

\frac{8 ( 2 ln ( 2 ) - 1 )}{e ^{4}}

Expand

8 (2 ln (2) - 1) : 16 ln (2) - 8

= \frac{16 ln ( 2 ) - 8}{e ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 ln ( 2 ) - 8}{e ^{4}} = \frac{16 ln ( 2 )}{e ^{4}} - \frac{8}{e ^{4}}

= \frac{16 ln ( 2 )}{e ^{4}} - \frac{8}{e ^{4}}

(2 x^{3} - 4 x + 5)^{6}

4 sin (2) (π - θ)

\frac{1 - n ^{2} x ^{2}}{( 1 + n ^{2} x ^{2} ) ^{2}}

\frac{x ( x - 4 )}{( x + 6 ) ( x - 2 )}

\frac{d x}{( x - 3 ) ^{3}}

What is expand (8(2ln(2)-1))/(e^4) ?
The solution to expand (8(2ln(2)-1))/(e^4) is (16ln(2))/(e^4)-8/(e^4)