What is expand ((-z-1)^2z^2)/4 ?

The solution to expand ((-z-1)^2z^2)/4 is (z^4)/4+(z^3)/2+(z^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((-z-1)^2z^2)/4

expand

\frac{( - z - 1 ) ^{2} z ^{2}}{4}

\frac{z ^{4}}{4} + \frac{z ^{3}}{2} + \frac{z ^{2}}{4}

Solution steps

\frac{( - z - 1 ) ^{2} z ^{2}}{4}

(- z - 1)^{2} = z^{2} + 2 z + 1

= \frac{z ^{2} ( z ^{2} + 2 z + 1 )}{4}

Expand

(z^{2} + 2 z + 1) z^{2} : z^{4} + 2 z^{3} + z^{2}

= \frac{z ^{4} + 2 z ^{3} + z ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{z ^{4} + 2 z ^{3} + z ^{2}}{4} = \frac{z ^{4}}{4} + \frac{2 z ^{3}}{4} + \frac{z ^{2}}{4}

= \frac{z ^{4}}{4} + \frac{2 z ^{3}}{4} + \frac{z ^{2}}{4}

Cancel

\frac{2 z ^{3}}{4} : \frac{z ^{3}}{2}

= \frac{z ^{4}}{4} + \frac{z ^{3}}{2} + \frac{z ^{2}}{4}

5 (e - 4)

\frac{\partial}{\partial x} ((z) (x sin (x y) - z))

(\frac{2 x ^{4}}{3 x})^{3}

\frac{1}{s ( s ^{2} + 3 s + 5 )}

\frac{x ^{2} ( - 10 x ^{3} + 3 x ^{2} - 60 x )}{20}

What is expand ((-z-1)^2z^2)/4 ?
The solution to expand ((-z-1)^2z^2)/4 is (z^4)/4+(z^3)/2+(z^2)/4