What is expand (x^2(-10x^3+3x^2-60x))/(20) ?

The solution to expand (x^2(-10x^3+3x^2-60x))/(20) is -(x^5)/2+(3x^4)/(20)-3x^3

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expand (x^2(-10x^3+3x^2-60x))/(20)

expand

\frac{x ^{2} ( - 10 x ^{3} + 3 x ^{2} - 60 x )}{20}

- \frac{x ^{5}}{2} + \frac{3 x ^{4}}{20} - 3 x^{3}

Solution steps

\frac{x ^{2} ( - 10 x ^{3} + 3 x ^{2} - 60 x )}{20}

Expand

x^{2} (- 10 x^{3} + 3 x^{2} - 60 x) : - 10 x^{5} + 3 x^{4} - 60 x^{3}

= \frac{- 10 x ^{5} + 3 x ^{4} - 60 x ^{3}}{20}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 10 x ^{5} + 3 x ^{4} - 60 x ^{3}}{20} = - \frac{10 x ^{5}}{20} + \frac{3 x ^{4}}{20} - \frac{60 x ^{3}}{20}

= - \frac{10 x ^{5}}{20} + \frac{3 x ^{4}}{20} - \frac{60 x ^{3}}{20}

Cancel

\frac{10 x ^{5}}{20} : \frac{x ^{5}}{2}

= - \frac{x ^{5}}{2} + \frac{3 x ^{4}}{20} - \frac{60 x ^{3}}{20}

Divide the numbers:

\frac{60}{20} = 3

= - \frac{x ^{5}}{2} + \frac{3 x ^{4}}{20} - 3 x^{3}

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\frac{d ^{2}}{d x ^{2}} ((y) (2 x^{2} - 4))

What is expand (x^2(-10x^3+3x^2-60x))/(20) ?
The solution to expand (x^2(-10x^3+3x^2-60x))/(20) is -(x^5)/2+(3x^4)/(20)-3x^3