What is expand (x^4-2x^2+2)(x^2-2x+3)' ?

The solution to expand (x^4-2x^2+2)(x^2-2x+3)' is x^4(x^2-2x+3)'-2x^2(x^2-2x+3)'+2(x^2-2x+3)'

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expand (x^4-2x^2+2)(x^2-2x+3)'

expand

(x^{4} - 2 x^{2} + 2) (x^{2} - 2 x + 3)^{'}

x^{4} (x^{2} - 2 x + 3)' - 2 x^{2} (x^{2} - 2 x + 3)' + 2 (x^{2} - 2 x + 3)'

Solution steps

(x^{4} - 2 x^{2} + 2) (x^{2} - 2 x + 3)^{'}

Distribute parentheses

= (x^{2} - 2 x + 3)^{^{'}} x^{4} + (x^{2} - 2 x + 3)^{^{'}} (- 2 x^{2}) + (x^{2} - 2 x + 3)^{^{'}} 2

Apply minus-plus rules

+ (- a) = - a

= x^{4} (x^{2} - 2 x + 3)^{^{'}} - 2 x^{2} (x^{2} - 2 x + 3)^{^{'}} + 2 (x^{2} - 2 x + 3)^{^{'}}

(2, 0, 2,) \cdot (x, 4, - 1) \cdot (3, 2, 1)

\frac{d ^{2}}{d x ^{2}} ((y) (2 x^{2} - 4))

(2 + 3 i) (2 - 3 i)^{'}

x (1 - x - x^{3} + x^{4})^{2}

cos (3 t) U (t - \frac{7 π}{2})

What is expand (x^4-2x^2+2)(x^2-2x+3)' ?
The solution to expand (x^4-2x^2+2)(x^2-2x+3)' is x^4(x^2-2x+3)'-2x^2(x^2-2x+3)'+2(x^2-2x+3)'