What is expand ((a-x)^3)/3 ?

The solution to expand ((a-x)^3)/3 is (a^3)/3-a^2x+ax^2-(x^3)/3

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expand ((a-x)^3)/3

expand

\frac{( a - x ) ^{3}}{3}

\frac{a ^{3}}{3} - a^{2} x + a x^{2} - \frac{x ^{3}}{3}

Solution steps

\frac{( a - x ) ^{3}}{3}

(a - x)^{3} = a^{3} - 3 a^{2} x + 3 a x^{2} - x^{3}

= \frac{a ^{3} - 3 a ^{2} x + 3 a x ^{2} - x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a ^{3} - 3 a ^{2} x + 3 a x ^{2} - x ^{3}}{3} = \frac{a ^{3}}{3} - \frac{3 a ^{2} x}{3} + \frac{3 a x ^{2}}{3} - \frac{x ^{3}}{3}

= \frac{a ^{3}}{3} - \frac{3 a ^{2} x}{3} + \frac{3 a x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{3}{3} = 1

= \frac{a ^{3}}{3} - a^{2} x + a x^{2} - \frac{x ^{3}}{3}

(- e^{x} sin (x) + cos (x) e^{x})^{2}

(y^{2} + 2^{y}) d y

(6 + 23) π

(x + 3 \circ x^{2}) \cdot 1

(2 x y) + (y^{2} - x^{2} - 4) y^{'} (x)

What is expand ((a-x)^3)/3 ?
The solution to expand ((a-x)^3)/3 is (a^3)/3-a^2x+ax^2-(x^3)/3